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5x^2+70x-148=0
a = 5; b = 70; c = -148;
Δ = b2-4ac
Δ = 702-4·5·(-148)
Δ = 7860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7860}=\sqrt{4*1965}=\sqrt{4}*\sqrt{1965}=2\sqrt{1965}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{1965}}{2*5}=\frac{-70-2\sqrt{1965}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{1965}}{2*5}=\frac{-70+2\sqrt{1965}}{10} $
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